Question

номер 733 помогите!!!!!!

Answer 1

$1)$

$\frac{1}{x}+\frac{3}{\frac{12}{5}x }=[tex]\frac{3}{4}$

$x\neq 0$

$\frac{1}{x}+\frac{5}{4x}=\frac{3}{4}$

$\frac{9}{4x} =\frac{3}{4}$

$36=12x$

$x=3$

$2)\\\frac{1}{x}-\frac{3}{7x} =\frac{2}{7}$

$\frac{4}{7x}=\frac{2}{7}$

$28=14x$

$x=2$

$3)\\\frac{6}{\frac{10x}{3} } +\frac{1}{x} =\frac{2}{5} \\\frac{9}{5x}=\frac{1}{x}=\frac{2}{5} \\\frac{14}{5x}=\frac{2}{5} \\70=10x \\x=7$