Question

Найдите первообразную функции

Answer 1

$f(x)=-\frac{1}{(6x+1)^2}\\\\F(x)=-\int \frac{dx}{(6x+1)^2}=-\frac{1}{6}\int (6x+1)^{-2} \cdot 6\, dx=-\frac{1}{6}\cdot \frac{(6x+1)^{-1}}{-1}+C=\\\\=\frac{1}{6\cdot (6x+1)}+C$