Question

$- 0.2( \sqrt{98} \times \sqrt{10} \ \ + \sqrt{1.8)}$срочно

Answer 1

$-\sqrt{0,2}(\sqrt{98}*\sqrt{10}+\sqrt{1,8})=-\sqrt{0,2}(\sqrt{49*2*2*5}+\sqrt{0,36*5})=-\sqrt{0,2}(7*2\sqrt{5}+0,6\sqrt{5})=-\sqrt{0,2}*14,6\sqrt{5}=-14,6}$