Question

Иррациональное уровнение. Нужно решение

Answer 1

$\sqrt{x^2+12}=6-x~~~~~~|~()^2\\\\x^2+12 = (6-x)^2\\\\x^2+12=36-12x+x^2\\\\x^2-x^2+12x=36-12\\\\12x=24~~~~\boxed{x=2}$

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Проверка :

$\sqrt{2^2+12}=6-2\\\\\sqrt{16}=4~~~~\Leftrightarrow~~~~4=4$

Answer 2

$\sqrt{x {}^{2} + 12} = 6 - x \\ x {}^{2} + 12 = 36 - 12x + {x}^{2} \\ 12 = 36 - 12x \\ 12x= 36 - 12 \\ 12x = 24 \\ x = 24 \div 12 \\ x = 2 \\ \sqrt{2 {}^{2} + 12} = 6 - 2 \\ 4 = 4 \\ x = 2$