Question

у=-х2-х+12 найди значение функцииF(3)F(-5)

Answer 1

F(x)=-x^3/3-x^2/2+12x

F(3)=-27/3 - 9/2 + 12*3=-9-4.5+36=22.5

F(-5)=125/3-25/2+12*(-5)=250/6 - 75/6 - 360/6=-185/6