Question

Найдите расстояние между корнями уравнениЯ 20x^2+x-1=0

Answer 1

$20 {x}^{2} + 5x - 4x - 1 = 0 \\ 5x(4x + 1) - (4x + 1) = 0 \\ (4x + 1)(5x - 1) = 0 \\ 4x + 1 = 0 \\ 5x - 1 = 0 \\ x1 = - 0.25 \\ x2 = 0.2$