Question

решите систему уравнений
${x}^{2} + {y}^{2} = 26 \\ x - y = - 4$

Answer 1

y = x+4

x²+(x+4)² = 26

2x²+8x+16 = 26

x²+4x -5 = 0

(x+5)(x-1) = 0

y = x+4

x₁ = -5, y₁ = -1

x₂ = 1, y₂ = 5