Question

(3x+1)²-(3x-2)(2+3x)=17

Answer 1

$9x^{2} +1-6x+9x-4-6x=17\\9x^{2} +1-6x+9x-4=17\\9x^{2} -12x +9x=17+1-4\\9x^{2} -3x=14\\x(9x-3)=14\\x=14,9x=14+3\\9x=17\\x=17:9\\x=1.9\\9*1.9-3=14.1$