Question

решите уравнение:
12-(4-Х)^2=Х(3-Х)

Answer 1

12-16-8x+x^2=3x^2-x^2

-4-8x+x^2-3x^2+x^2=0

x^2-8x-4=0

D=64-4×1×-4=64+16=80

x1=8+√80/2=8+4√5/2=6√5

x2=8-4√5/2=2√5

Ответ: x1=6√5,x2=2√5