Question

помогите а б г сделать прошууу

Answer 1

$\frac{x}{x - y} - \frac{x {}^{2} }{x {}^{2} - y {}^{2} } \\ \frac{x}{x - y} - \frac{x {}^{2} }{(x - y)(x + y) } \\ \frac{x(x + y) - x {}^{2} }{(x - y)(x + y)} \\ \frac{x {}^{2} + xy - x {}^{2} }{x {}^{2} - y {}^{2} } = \frac{xy}{x {}^{2} - y {}^{2} } \\ \frac{ax}{a {}^{2} - x {}^{2} } - \frac{a - x}{a + x} \\ \frac{ax}{(a - x)(a + x)} - \frac{a - x}{a + x} \\ \frac{ax - (a - x) {}^{2} }{(a - x)(a + x)} \\ \frac{ax - (a {}^{2} - 2ax + x { }^{2} ) }{a {}^{2} - x {}^{2} } \\ \frac{ax - a {}^{2} + 2ax - x {}^{2} }{a {}^{2} - x {}^{2} } = \frac{3ax - a {}^{2} - x {}^{2} }{a {}^{2} - x {}^{2} } \div \frac{3}{2a + 5} - \frac{3a - 10}{4a {}^{2} - 25} \\ \frac{3}{2a + 5} - \frac{3a - 10}{(2a - 5)(2a + 5)} \\ \frac{3(2a - 5) - (3a - 10)}{(2a + 5)(2a - 5)} \\ \frac{6a - 15 - 3a + 10}{4a {}^{2} - 25 } = \frac{3a - 5}{4a {}^{2} - 25 }$