Question

Помогите, пожалуйста, с заданиями 3 и 4

Answer 1

$3.) \\ 2 {}^{ \frac{2x + 4}{3} } = 2 {}^{ \frac{9}{5} } \\ \frac{2x + 4}{3} = \frac{9}{5} \\ 5(2x + 4) = 3 \times 9 \\ 10x + 20 = 27 \\ 10x = 27 - 20 \\ 10x = 7 \\ x = \frac{7}{10} \\ 4.) \\ (3 {}^{2} + 3 - 1) \times 3 {}^{2 \sqrt{x} - 2} = 11 \\ 11 \times 3 {}^{2 \sqrt{x} - 2 } = 11 \\ 3 {}^{2 \sqrt{x} - 2 } = 11 \\ 3 {}^{2 \sqrt{x} - 2} = 3 {}^{0} \\ 2 \sqrt{x} - 2 = 0 \\ 2 \sqrt{x} = 2 \\ \sqrt{x} = 1 \\ x = 1$

Answer 2

3)³√4^(х+2)=4/2^1/2

2^(2х+4)/3=2^(2-1/5)

(2х+4)/3=9/5

2х+4=27/5

2х=27/5-4

2х=7/5

х=7/10

х=0,7

4)3^2√х=а

а(1+1/3-1/9)=11

а*(9+3-1)/9=11

а*11/9=11

а=9

3^(2√х)=3²

2√х=2
√х=1
х=1