Question

1. 9(a+1)^2-1
2. (1-3x)(1-12x)=11-(5-6x)(6x+5)

Answer 1

1)
$9 {(a + 1)}^{2} - 1 = 9( {a}^{2} + 2a + 1) - 1 \\ = 9 {a}^{2} + 18a + 9 - 1 = \\ 9 {a}^{2} + 18a + 8$
2)
$(1 - 3x)(1 - 12x) = \\ 11 - (5 - 6x)(6x + 5) \\ 1 - 12x - 3x + 36 {x}^{2} = \\ 11 - (25 - 36 {x}^{2} ) \\ 1 - 15x + 36 {x}^{2} = 11 - 25 + 36 {x}^{2} \\ 1 - 15x = 11 - 25 \\ - 15x = - 14 - 1 \\ - 15x = - 15 \\ x = 1$