Question

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y^2+1,4y+0,49−36y^2=0

Answer 1

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Вот ваше решение:

$y^{2} +1.4y + 0.49 - 36y^{2} =0\\-35y^{2} +\frac{7}{5} + \frac{49}{100} = 0\\-3500y^{2}+140y+49=0\\ 500y^{2}-20y-7=0\\ 500y^{2} +50y-70y-7=0\\50y(10y+1)-7(10y+1)=0\\(10y+1)(50y-7)=0\\10y + 1 =0\\50y - 7 = 0\\y_{1} = -\frac{1}{10} = -0.1\\y_{2} = \frac{7}{50} = 0.14$