Question

Решите пожалуйста систему))

Answer 1

$x - 5y = 3 \\ xy + 3y = 11 \\ x = 3 + 5y \\ y(3 + 5y) + 3y= 11 \\ 3y + 5 {y}^{2} + 3y = 1 \\ 5 {y}^{2} + 6y - 11 = 0 \\ d = 36 + 4 \times 5 \times 11 = 256 \\ y1 = \frac{ - 6 + 16}{10} = 1 \\ y2 = \frac{ - 6 - 16}{10} = - 2.2 \\ x1 = 3 + 5 \times 1 = 8 \\ x2 = 3 + 5 \times ( - 2.2) = - 8$