Question

а⁵-а¹² + 2а⁶ - a⁵
x²+x = 4
x - x² = 0

Answer 1

а^5-а^12+ 2а^6- a^5=2a^6-a^12=a^6×(2-a^6).

x²+x = 4
x²+x-4=0
D=(-1)²-4×1×(-4)=1+16=17
x1=(-1-√17)/2×1=(-1/2)-(√17)/2=-0,5-(√17)/2
x2=(-1+√17)/2×1=(-1/2)+(√17)/2=-0,5+(√17)/2.

x - x² = 0
x×(1-x)=0
x1=0
1-x2=0
-x2=-1|×(-1)
x2=1