Question

Решите пожалуйста $x^{2} -5x-1=0$

Answer 1

$x^{2} -5x-1=0\\D=b^{2} -4ac=25+4=29\\x_{12} =\frac{-b\frac{+}{-} \sqrt{D} }{2a} = \frac{-5\frac{+}{-} \sqrt{29} }{2}$