Question

ПОМОГИТЕ ДАМ 35 БАЛЛОВ!!!
в вложении

Answer 1

1.
$(1.3x) ^{2} \times (1.3x )^{3} \times {(1.3x)}^{4} = (1.3x) ^{2 + 3 + 4} = (1.3x) ^{9}$
$(2.7a) ^{3} \times {(2.7a)}^{5} \times (2.7a) = {(2.7a)}^{3 + 5 + 1} = {(2.7a)}^{9}$
$(2a + 1) ^{2} \times {(2a + 1)} \times {(2a + 1)}^{3} = {(2a + 1)}^{2 + 1 + 3} = {(2a + 1)}^{6}$
$(1 - 3x) \times {(1 - 3x)} ^{3} \times (1 - 3x) ^{5} = {(1 - 3x)}^{1 + 3 + 5} = {(1 - 3x)}^{8}$
2.
${3}^{9} \div {3}^{2} = {3}^{9 - 2} = {3}^{7}$
${5}^{7} \div {5}^{3} = {5}^{7 - 3} = {5}^{4}$
$( - 0.7) ^{10} \div ( - 0.7) ^{7} = {( - 0.7)}^{10 - 7} = {( - 0.7)}^{3}$
$(- \frac{1}{3} ) ^{5} \div ( - \frac{1}{3}) ^{3} = ( - \frac{1}{3}) ^{5 - 3} =( - \frac{1}{3}) ^{2}$
${4}^{10} \div {4}^{2} \div 4 = {4}^{10 - 2 - 1} = {4}^{7}$
${10}^{9} \div 10 \div {10}^{5} = {10}^{9 - 1 - 5} = {10}^{3}$