Question

Даю 20 баллов!!! Срочно!!!
${x}^{5} - {x}^{4} - {2x}^{3} + {2x }^{2} + x - 1 = 0$

Answer 1

${x}^{5} - {x}^{4} - 2 {x}^{3} + 2 {x}^{2} + x - 1 = 0 \\ {x}^{4} (x - 1) - 2 {x}^{2} (x - 1) + (x - 1) = 0 \\ (x - 1)( {x}^{4} - 2 {x}^{2} + 1) = 0 \\ x = 1\: \: \: and \: \: \: {( {x}^{2} - 1) }^{2} = 0 \\ x = 1\: \: \: and \: \: \: x = 1 \: \: \: and \: \: \: x = - 1$
Ответ:х=±1