Question

решите уравнения
(х-5) ²=0
(х+3)²=1
(х-1)(х+2)=0
(х-1) ²=1

Answer 1

$(x-5)^2=0\\x-5=0\\x=5\\\\(x+3)^2=1\\x^2+6x+9=1\\x^2+6x+8=0\\\begin{cases}x+3=1\\x+3=-1\end{cases}\Rightarrow\begin{cases}x_1=-2\\x_2=-4\end{cases}\\\\\\(x-1)(x+2)=0\\\begin{cases}x-1=0\\x+2=0\end{cases}\Rightarrow\begin{cases}x_1=1\\x_2=-2\end{cases}\\\\\\(x-1)^2=1\\\begin{cases}x-1=1\\x-1=-1\end{cases}\Rightarrow\begin{cases}x_1=2\\x_2=0\end{cases}$