Question

log 12 4,25= log 12 x− log 12 18

Answer 1

$log_{12}4,25=log_{12}x-log_{12}18\\log_{12}4,25-log_{12}x+log_{12}18=0\\log_{12}4,25/x*18=0\\log_{12}76,5/x=0\\12^0=76,5/x\\x=76,5$

Answer 2

Log_(12) 4,25=log_(12)x-log_(12)18   ODZ: x> 0

Log_(12)x=log_(12)4,25+log_(12)18

Log_(12) x=log_(12)  (4,25*18)

  X=4,25*18

X=76,5