Question

Решите пожалуйста. НЕ ПОЛНЫЕ КВАДРАТНЫЕ УРАВНЕНИЯ! !!!
$x {}^{2} - 196 = 0 \\ 1.7x {}^{2} = 0 \\ 8x {}^{2} = 128 \\ 3x {}^{2} - 48 = 0 \\ 7x {} {}^{6} - x = 0 \\ x = - 25$

Answer 1

1)$x^{2} -196=0\\x^{2} - 14^{2} =0\\(x-14)(x+14)=0\\\left \{ {{x-14=0} \atop {x+14=0}} \right. \\\left \{ {{x=14} \atop {x=-14}} \right.$

2)$1.7x^{2} =0\\x^{2} =0\\x=0$

3)$8x^{2} =128\\x^{2} =\frac{128}{8} =16\\x=\frac{+}{-} 4$

4)$3x^{2} -48=0\\3x^{2} =48\\x^{2} =16\\x=\frac{+}{-} 4$

5)$7x^{6} -x=0\\x(7x^{5} -1)=0\\x=0\\7x^{5} -1=0\\7x^{5} =1\\x^{5} =\frac{1}{7} \\x=\sqrt[5]{\frac{1}{7} }$