Question

x^2-12x+29=0
Помогите пж

Answer 1

$x^{2}-12x+29=0\\\\D=(-12)^{2}-4*29=144-116=28\\\\x_{1}=\frac{12+\sqrt{28} }{2}=\frac{12+2\sqrt{7} }{2}=6+\sqrt{7}\\\\x_{2}=\frac{12-\sqrt{28} }{2}=\frac{12-2\sqrt{7} }{2}=6-\sqrt{7}$