Question

4х^2+5х+1=0

помогите решить уравнение

Answer 1

$4x^{2} +5x+1=0\\D=5^{2} -4*4*1=25-16=9\\x_{1} = \frac{-5-3}{8} =-1\\x_{2} =\frac{-5+3}{8} =-\frac{1}{4}$

Answer 2

D=25-4*4=9

x1=(-5+3)/8; x2=(-5-3)/8

x1=-1/4; x2=-1