Question

решите через дискриминант и найдите x1,2. потом просто x1 x2

Answer 1

$a)3 {x}^{2} + 13x - 10 = 0 \\ d = 169 + 3 \times 4 \times 10 = 289 \\ x1 = \frac{ - 13 + 17}{6} = \frac{4}{6} = \frac{2}{3} \\ x2 = \frac{ - 13 - 17}{6} = - 5 \\ b)2 {x}^{2} - 3x = 0 \\ x(2x - 3) = 0 \\ x1 = 0 \: \: \: x2 = \frac{3}{2} = 1.5 \\ v)16 {x}^{2} = 49 \\ 16 {x}^{2} - 49 = 0 \\ (4x - 7)(4x + 7) = 0 \\ 4x - 7 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 4x + 7 = 0\\ x 1 = \frac{7}{4} = 1 \frac{3}{4} \: \: \: \: \: \: \: \: x2 = - \frac{7}{4} = - 1 \frac{3}{4} \\ r) {x }^{2} - 2x - 35 = 0 \\ x1 = 7 \\ x2 = - 5$