Question

ответ на листке пж86(а;б;в) 87(а;б)

Answer 1

№85а) $arcsin\frac{\sqrt{2} }{2} =\frac{\pi}{4}$

б) $arccos\frac{\sqrt{3} }{2} =\frac{\pi }{6}$

в) $arctg\frac{1}{\sqrt{3} } =\frac{\pi }{6}$

г) $arccos(-\frac{\sqrt{2} }{2} )=\pi -\frac{\pi }{4} =\frac{3\pi }{4}$

д) $arcsin(-\frac{\sqrt{3} }{2} )=-arcsin(\frac{\sqrt{3} }{2} )=\frac{\pi}{3}$

е)$arctg(-\frac{\sqrt{3} }{3})=-\frac{\pi }{6}$

№ 86а) arctg1-arctg$\sqrt{3}=\frac{\pi }{4} -\frac{\pi }{3} =(\frac{3}{12} -\frac{4}{12} ) *\pi =-\frac{\pi}{12}$

б) $arcsin\frac{\sqrt{2} }{2} +arccos\frac{1}{2}=\frac{\pi }{4} +\frac{\pi }{3}=\frac{7\pi }{12}$