Question

Найдите экстремумы функции

Answer 1

$y = 3 {x}^{2} - 6x - 9 = 0 \\ {x}^{2} - 2x - 3 = 0 \\ x1 = - 1 \\ x2 = 3 \\ \\ fmax( - 1) = 3 \\ fmin(3) = - 31$