Question

Даю 100 баллов. Срочно !

Answer 1

$\left \{ {{2-4y\geq2y-10 } \atop {3>3(y+3)}} \right.\\\\\left \{ {{-4y-2y\geq-10-2 } \atop {y+3<1}} \right.\\\\\left \{ {{-6y\geq-12 } \atop {y<-2}} \right.\\\\\left \{ {{y\leq2 } \atop {y<-2}} \right.$

Ответ : y ∈ (- ∞ ; - 2)