Question

(x-3)^2+(3-x)(3+x)=(x+2)^2-x^2
уравнение

Answer 1

${(x - 3)}^{2} + (3 - x)(3 + x) = {(x + 2)}^{2} - {x}^{2}$
${(x - 3)}^{2} + 9 - {x}^{2} = {x}^{2} + 4x + 4 - {x}^{2}$
${x}^{2} - 6x + 9 + 9 = {x}^{2} + 4x + 4$
$- 6x + 9 + 9 = 4x + 4$
$- 6x + 18 = 4x + 4$
$- 6x - 4x = 4 - 18$
$- 10x = - 14$
$x = \frac{7}{5} = 1 \frac{2}{5} = 1.4$

Answer 2

Ответ:

x=7/5

Пошаговое объяснение:

X²-6X+9+9+3X-3X-X²=X²+4X+4-X²

-6x+18=4x+4

-10x=-14

x=14/10

x=7/5