Question

решите уравнение sin(п/2+2х)=sinx

Answer 1

$\cos(2x) = \sin(x) \\ 1 - 2 { \sin(x) }^{2} = \sin(x) \\ 1 - { \sin(x) }^{2} - \sin(x) = 0 \\ 1 - 2 {t}^{2} - t = 0 \\ t = \frac{1}{2} \\ t = - 1 \\ \sin(x) = \frac{1}{2} \\ \sin(x) = - 1$