Question

9y(y+6)-(3y+1)²=1 как решать уравнение

Answer 1

$9y(y + 6) - (3y + 1) {}^{2} = 1 \\ 9y {}^{2} + 54y - (9y {}^{2} + 6y + 1) = 1 \\ 9y {}^{2} + 54y - 9y {}^{2} - 6y - 1 = 1 \\ 48y = 1 + 1 \\ 48y = 2 \\ y = \frac{1}{24}$

Answer 2

У=1/24..........))))))