Question

Помогите решить!!!!!!!!!

Answer 1

$3x^{2} +2x-1=0\\D= b^{2} -4ac = 4-4*3*(-1) = 4-(-12)=4+12=16\\x1,2= \frac{-b+-\sqrt{D} }{2a} = \frac{-2+-4}{6}\\x1=2/6=1/3\\x2=-6/6=-1$

Дискриминант равен 16