Question

РЕШИТЕ ПОЖАЛУЙСТА!!!!

Answer 1

$\frac{3p^{2}+13p-10}{12-16p-3p^{2} } = \frac{3p^{2} +15p-2p - 10}{-3p^{2}-16p+12 } = \frac{3p*(p+5)-2(p+5}{-3p^{2}+2p - 18p +12 }= \frac{(p+5) * (3p-2)}{-p*(3p-2) - 6(3p-2)} = \frac{(p+5) * (3p-2)}{-(3p-2) * (p+6)} = \frac{(p+5)*(-1)}{p+6} = -\frac{p+5}{p+6}$

Answer 2

3р^2-13р-10=0

D=169-4*3*(-10)=169+120=✓289=17
D=256-4*3(-12)=256+144=✓400=20
17/20=0.85