Question

ПОМОГИТЕ РЕШИТЬ!!! Систему неравенств
1. {2x-1<1,4-x
{3x-2>x-4
2. {5(x-2)-x>2
{1-3(x-1)<-2
3. 3(2-3p)-2(3-2p) >p
6

Срочоо

Answer 1

$\displaystyle\left \{ {{2x-1<1,4-x} \atop {3x-2>x-4}} \right. \left \{ {{2x+x<1,4+1} \atop {3x-x>2-4}} \right. \left \{ {{3x<2,4} \atop {2x>-2}} \right.\left | {{:3} \atop {:2}} \\\left \{ {{x<0,8} \atop {x>-1}} \right. \\\left \{ {{++++++(0,8)->x} \atop {-(-1)++++++>x}} \right.$

$x\in(-1;0,8)$

Ответ: $(-1;0,8)$

$\displaystyle \left \{ {{5(x-2)-x>2} \atop {1-3(x-1)<-2}} \right. \left \{ {{5x-10-x>2} \atop {1-3x+3<-2}} \right. \left \{ {{4x>12} \atop {-3x<-6}} \right. \left |{ {{:4} \atop {:(-3)}} \right. \\\\\left \{ {{x>3} \atop {x>2}} \right. \left \{ {{-------(3)++>x} \atop {-----(2)++++>x}} \right. \\x\in(3;+\infty)$

Ответ: (3;+\infty)