Question

y=ln(x+1+√(x^2+2x+3) )
Найти производную функции

Answer 1

$y = (x + 1 + \sqrt{ {x}^{2} + 2x + 3} )dx\times \frac{1}{x + 1 + \sqrt{ {x}^{2} + 2x + 3 } } = 1 + \frac{2(x + 1)}{(x + 1) \sqrt{ {x}^{2} + 2x + 3 } + {x}^{2} + 2x + 3 }$