Question

срочно!!! алгебра!!! 1 вариант

Answer 1

$N1\\x^2+12x+36=0\\(x+6)^2=0\\x=-6\\Otvet: -6\\\\x^2-8x+15=0\\(x-4)^2=1\\x-4=^+_-1\\x_1=3\\x_2=5\\Otvet:3;5\\\\x^2-5x-6=0\\x^2-2\frac{5}{2}+\frac{25}{4}=6+\frac{25}{4}\\(x-\frac{5}{2})^2=\frac{49}{4}\\x-\frac{5}{2}=^+_-\frac{7}{2}\\x_1=-1\\x_2=6\\Otvet:-1;6\\\\N2\\2x^2-9x+10=0\\a=2; b=-9; c=10\\b^2-4ac=(-9)^2-4*2*10=81-80=1\\\\-x^2+x-5=0\\a=-1;b=1;c=-5\\b^2-4ac=1^2-4*(-1)*(-5)=1-20=-19$