Question

Как это решить????ПОМОГИТЕ!!

Answer 1

$2 \times {2}^{2d} - 5 \times {6}^{d} + 3 \times {3}^{2d} = 0 \\ ( {2}^{d} - {3}^{d} )( {2}^{d + 1} - {3}^{d + 1} ) = 0 \\ {2}^{d} = {3}^{d} \\ d = 0 \\ {2}^{d + 1} = {3}^{d + 1} \\ d + 1 = 0 \\ d = - 1$