Question

срочно помогите даю 15 балов

Answer 1

$\frac{1}{6} +x-\frac{1}{2} = -\frac{1}{3} +x$;

c✖4$-\frac{1}{5} = 4c$➖$\frac{1}{5}$;

a➖$\frac{4}{9}$➖$\frac{1}{3}$=a➖$\frac{7}{9}$;

y➗3➖$\frac{2}{7}$ = $\frac{1 }{3} y$➖$\frac{2}{7}$=$\frac{1}{21}$✖(7y➖6);