Question

вычислить
$log_{6}12 - log_{ \frac{1}{6} }3$

Answer 1

$log_{6}(12) - log_{6}( {3}^{ - 1} ) = log_{ 6 }12 + log_{6}(3) = log_{6}(12 \times 3) = log_{6}(36) = 2$