Question

(a²-2)²-(a²-1)(a²+2)+5(a-4)², якщо a=-0,125

Answer 1

$\tt \ \ \ (a^2-2)^2-(a^2-1)(a^2+2)+5(a-4)^2=\\ =a^4-4a^2+4-(a^4+2a^2-a^2-2)+5(a^2-8a+16)=\\ =a^4-4a^2+4-a^4-2a^2+a^2+2+5a^2-40a+80= \\=86-40a\\\\ npu \ a=-0,125\\\\ 86-40a=86-40(-0,125)=86+5=91$

Ответ: 91.