Question

Определите массовые доли каждого элемента в веществе.Даю 17 баллов,
Вещество-Cu(NO3)2

Answer 1

w(Cu) = 64 * 1 / 188 = 34%

w(N) = 14 * 2 / 188 = 15%

w(O) = 16 * 6 /188 = 51%

Answer 2

дано

Cu(NO3)2

----------------

W(Cu)-?

W(N)-?

W(O)-?

M(Cu(NO3)2 = 64+(14+16*3)*2 = 188 g/mol

W(Cu) = 64 / 188 * 100% = 34.04%

W(N) = 14*2 /* 188 * 100% = 14.89%

W(O) = 16*6 / 188 * 100% =51.07%