Question

решите...
1) (x\y)² при x = -6 и y = -1,5; x = 0 и y = -23.
2) (x+y)⁴ при x = 0,7 и y = 0,3; x = -11 и y = -6.
3)(y-x)³ при x = -14 и y = -10; x =0,9 и y = 1,1

Answer 1

#1

$\boxed{\;\bf (\frac{x}{y} )^{2} \ esli \ x=-6, y=-1.5 \ ili \ x=0, y=-23 \;}\\\\\left[\begin{array}{ccc}(\frac{-6}{-1.5})^2=4^2=16\end{array}\right] \\\\\left[\begin{array}{ccc}(\frac{0}{-23})^2=0^2=0\end{array}\right]$

#2

$\boxed{\;\bf (x+y )^{4} \ esli \ x=0.7, y=0.3 \ ili \ x=-11, y=-6 \;}\\\\\left[\begin{array}{ccc}(0.7+0.3)^4=1^4=1\end{array}\right] \\\\\left[\begin{array}{ccc}(-11-6)^4=(-17)^4=83521\end{array}\right]$

#3

$\boxed{\;\bf (y-x)^{3} \ esli \ x=-14, y=-10 \ ili \ x=0.9, y=1.1 \;}\\\\\left[\begin{array}{ccc}(-10-(-14))^3=(-10+14)^3=4^3=64\end{array}\right] \\\\\left[\begin{array}{ccc}(1,1-0,9)^3=0,2^3=0,008\end{array}\right]$