Question

Помогите, пожалуйста решить.

Answer 1

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

Answer 2

$\displaystyle\tt\frac{2^{4m-1}\cdot\bigg(\cfrac{1}{3}\bigg)^{2-2m}}{12^{2m-2}}= \frac{2^{4m-1}\cdot3^{-(2-2m)}}{(2^2\cdot3)^{2m-2}}= \frac{2^{4m-1}\cdot3^{2m-2}}{2^{4m-4}\cdot3^{2m-2}}=2^{4m-1-(4m-4)}=2^3=8$