Предмет: Физика, автор: makkaka

энергия заряженного конденсатора равна 500 джоулей а емкость конденсатора равна 1 ф определите напряжение которому он подключён

Ответы

Автор ответа: fatt52

1

W=500 Дж C=1 Ф U=?

===

W=C*U²/2

U=√(2*W/C)=√(2*500/1)=31.6 B

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makkaka: спасибо большое

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