Question

решите эту дичь, даю 40 балов

Answer 1

1) $\frac{4c-3d}{cd} -\frac{c-3d}{c} =\frac{4c-3d}{cd}-\frac{d*(c-3d)}{cd}</p><p>=\frac{4c-3d-cd+3d}{cd}$=$\frac{4c-cd}{cd} =\frac{c(4-d)}{cd} </p><p>=\frac{4-d}{d}$

2) $\frac{x+5}{x-5} -\frac{x-1}{x+5} </p><p>=\frac{(x+5)^{2}}{(x+5)(x-5) } -\frac{(x-1)(x-5)}{(x-5)(x+5)}$=

$\frac{x^{2}+10 x+25}{x^{2} -25} -\frac{x^{2} -x-5x+5}{x^{2} -25}$=

$\frac{x^{2}+10 x+25-x^{2}+6x-5 }{x^{2} -25 } =\frac{16x-20}{x^{2}-25}$

3)  $x+\frac{1}{x} =\frac{x^{2} }{x} +\frac{1}{x} =\frac{x^{2} +1}{x}$

$4) \frac{32a^{5}}{15y^{3}}:\frac{4a^{3} }{45y^{4}}  </p><p>=\frac{32a^{5}*45y^{4}  }{15y^{3}4a^{3}  }$=$\frac{8*4a^{2}*a^{3} *15*3*y^{3}*y  }{15y^{3}*4a^{2}  } =\frac{8*a^{2}*3y }{1} =24a^{2} y$