Question

(-y^2+3y-9)*2y/y^3+27

Answer 1

-(-y^2+3у-9)•2у/(у+3)(у^2-3у+9)=-2у/у+3

Answer 2

(-у+3у-9)·$\frac{2y}{y^{3}+27 }$ = (y²-3y+9) · $\frac{2y}{(y+3) * (y^{2} - 3y +9)}$ = -$\frac{2y}{y+3}$