Question

Срочно плизззззззззззз

Answer 1

$(\frac{s^2-5s+25}{25s^2-1} * \frac{5s^2+s}{s^3 + 125} - \frac{s+5}{5s^2-s}):\frac{4}{s^2+5s} - \frac{25s+22}{4-20s}$

$(\frac{s^2-5s+25}{(5s-1)(5s+1)} * \frac{s(5s+1)}{(s+5)(s^2-5s+125)} - \frac{s+5}{s(5s-1)})*\frac{s(s+5)}{4} - \frac{25s+22}{-4(5s-1)}$

$(\frac{s(5s+1)(s^2-5s+25)}{(5s-1)(5s+1)(s+5)(s^2-5s+125)} - \frac{s+5}{s(5s-1)})*\frac{s(s+5)}{4} + \frac{25s+22}{4(5s-1)}$

$(\frac{s^2}{s(5s-1)(s+5)} - \frac{(s+5)^2}{s(5s-1)(s+5)})*\frac{s(s+5)}{4} + \frac{25s+22}{4(5s-1)}$

$(\frac{s^2-(s+5)^2}{s(5s-1)(s+5)})*\frac{s(s+5)}{4} + \frac{25s+22}{4(5s-1)}$

$\frac{(s-s-5)(s+s+5)}{s(5s-1)(s+5)}*\frac{s(s+5)}{4} + \frac{25s+22}{4(5s-1)}$

$\frac{-5(2s+5)}{s(5s-1)(s+5)}*\frac{s(s+5)}{4} + \frac{25s+22}{4(5s-1)}$

$\frac{-5s(2s+5)(s+5)}{4s(5s-1)(s+5)} + \frac{25s+22}{4(5s-1)}$

$\frac{-5(2s+5)}{4(5s-1)} + \frac{25s+22}{4(5s-1)}$

$\frac{-5(2s+5)+25s+22}{4(5s-1)}$

$\frac{-10s-25+25s+22}{20s-4}$

$\frac{15s-3}{20s-4}$

$\frac{3(5s-1)}{4(5s-1)}$

$\frac{3}{4}$

Ответ: $\frac{3}{4}$