Question

помогите решить
$\sqrt[3]{27}$
$2 \sqrt[3]{8}$
$3 \sqrt[4]{16}$
$(2 \sqrt[3]{3) {}^{3} }$

Answer 1

$\sqrt[3]{27} = \sqrt[3]{ {3}^{3} } = 3 \\ 2 \sqrt[3]{8} = 2 \times \sqrt[3]{ {2}^{3} } = 2 \times 2 = 4 \\ 3 \sqrt[4]{16} = 3 \times \sqrt[4]{2 {}^{4} } = 6 \\ (2 \sqrt[3]{3 })^{3} = 8 \times 3 = 24$