Question

cos (x-pi/6)=корень из 3/2

Answer 1

$cos (x-\frac{\pi }{6})=\frac{\sqrt{3}}{2}$

$x-\frac{\pi }{6}=бarccos\frac{\sqrt{3}}{2}+2\pi n,$  $n$ ∈ $Z$

$x-\frac{\pi }{6}=б\frac{\pi}{6}+2\pi n,$  $n$ ∈ $Z$

$x=\frac{\pi }{6} б\frac{\pi}{6}+2\pi n,$  $n$ ∈ $Z$

$x=2\pi n,$  $n$ ∈ $Z$     или   $x=\frac{\pi }{3} +2\pi m,$  $m$ ∈ $Z$