Question

Помогите срочно!!!

$(\sqrt[4]{3} - \sqrt[4]{27})^2 : (6-4\sqrt{3})$

Answer 1

$\frac{(\sqrt[4]{3}-\sqrt[4]{27})^2 }{6-4\sqrt{3}}=\frac{\sqrt3-2\sqrt[4]{3\cdot 27}+\sqrt{27}}{6-4\sqrt3}=\frac{\sqrt3-2\cdot \sqrt[4]{3^4}+3\sqrt3}{6-4\sqrt3}=\frac{4\sqrt3-2\cdot 3}{6-4\sqrt3}=\\\\=\frac{4\sqrt3-6}{6-4\sqrt3}=\frac{-(6-4\sqrt3)}{6-4\sqrt3}=-1$