Question

1/3tg3x=-корень из 3/3

Answer 1

$\frac{1}{3} tg3x=-\frac{\sqrt{3} }{3}$

$tg3x=-\frac{\sqrt{3} }{3} :\frac{1}{3}$

$tg3x=-\frac{\sqrt{3} }{3} *3$

$tg3x=-\sqrt{3}$

$3x=arctg(-\sqrt{3})+\pi n,$  $n$ ∈ $Z$

$3x=-arctg\sqrt{3}+\pi n,$  $n$ ∈ $Z$

$3x=-\frac{\pi}{3} +\pi n,$  $n$ ∈ $Z$

$x=-\frac{\pi}{9} +\frac{\pi n }{3} ,$  $n$ ∈ $Z$